Another PR Question

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dhallnc

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Joined
Nov 2, 2010
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219
Location
Kings Mountain, NC
Can someone give me a good idea as to how much PR is required to fill a known area. I.E - X oz of pr = 1 cubic inch, or however you guys figure it out.

Thanks.
 
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it's about .55 oz/cu. in. but it would depend on the type of resin. But that's
a good starting point.
 
My math sucks when it comes to figuring this stuff but I just cast a couple of blanks this afternoon. One was a 3/4" PVC tube 6" long. It measured out to 2 oz. of resin. A 1/2" tube 6" long measured out at 1 oz.

FWIW
 
Darryl,
Fill the mold with water, empty the water into a plastic cup, mark the level and empty the cup.

Fill to line with PR. Add drops of catalyst, all will be well.
 
Darryl,
Fill the mold with water, empty the water into a plastic cup, mark the level and empty the cup.

Fill to line with PR. Add drops of catalyst, all will be well.

Good answer, Ed. Except somewhere in this method (the same method I use) you do need to know how many ounces so that you can add the correct amount of catalyst.
 
Sorry, Andy is correct.

We use cups that are nine ounces when full---Dawn approximates the drops:eek::eek::eek: (although most of the molds we now know the exact amount of resin).
 
To be clear, when you say resin are you referring to just resin, or catalysis and resin? Also will the resin not shrink and require more volume than plain water?
 
The formula for volume of a cylinder...

  • Cylinder = pi × radius2 × height
For a 3/4" x 6" mold it comes out to...2.6517857142857117 cu. in.

Convert to fluid ozs. is...1.469388 ozs. of resin.

So make your mold 6.5" and mix 1.5 ozs. of resin. :wink:
 
What I did was fill the mold with water, poured into a measuring cup to see how much water it was, then poured into mixing cup and marked it. Then all you have to do is put the correct number of drops per ounce in the mixing cup.
 
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